Isotope counting: how many neutrons are present in the nucleus of Uranium-233 (denoted 92U233)?

Difficulty: Easy

Correct Answer: 141

Explanation:


Introduction / Context:
Interpreting nuclide notation is a basic skill in nuclear science. The superscript denotes the mass number A (total protons + neutrons), and the subscript is the atomic number Z (protons). The difference A − Z yields the number of neutrons N in the nucleus.


Given Data / Assumptions:

  • Nuclide: Uranium-233 with A = 233 and Z = 92 (uranium).
  • We want N, the neutron count.


Concept / Approach:
The relationship N = A − Z is universal for nuclides. Using Uranium-233 values gives a straightforward arithmetic result.


Step-by-Step Solution:

1) Write the known values: A = 233, Z = 92.2) Compute neutrons: N = A − Z = 233 − 92.3) Evaluate: N = 141.


Verification / Alternative check:
Compare with Uranium-235, which has N = 235 − 92 = 143, confirming that U-233 has two fewer neutrons than U-235, consistent with isotope definitions.


Why Other Options Are Wrong:

  • 92: equals proton number (Z), not neutrons.
  • 233: total nucleons, not neutrons alone.
  • 325: not physically related to A or Z here.
  • 115: incorrect subtraction.


Common Pitfalls:
Mixing up A and Z; forgetting that A includes both protons and neutrons. Always verify with N = A − Z.


Final Answer:
141

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