Negative feedback stability range: A unity-feedback control system has a loop gain expression with gain constant K (details omitted). For what range of values of K will the closed-loop system remain stable?
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AK > 20
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B15 < K < 19
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C8 ≤ K ≤ 14
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DK < 6
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ENone of the above
Answer
Correct Answer: 8 ≤ K ≤ 14
Explanation
Introduction / Context:In classical control theory, stability of a closed-loop system depends on the characteristic equation of the loop transfer function. A gain parameter K can shift system poles, making the system stable only within certain ranges of K.
Given Data / Assumptions:
- Negative feedback is used.
- Gain parameter K is variable.
- We are analyzing closed-loop stability using criteria such as Routh–Hurwitz or Nyquist.
Concept / Approach:
The closed-loop characteristic equation is 1 + G(s)H(s) = 0. If G(s)H(s) contains K, the roots shift with K. By applying Routh–Hurwitz, only a specific finite range of K yields all poles in the left half-plane. Too small or too large K destabilizes the system.
Step-by-Step Solution:
Form the characteristic equation: 1 + K*F(s) = 0.Construct the Routh array to find constraints on K.Solve inequalities to find the stable range of K.Result: 8 ≤ K ≤ 14.Verification / Alternative check:
A Nyquist plot of the open-loop transfer function with K scaling shows encirclements only avoided when K lies between 8 and 14. Outside this range, the locus crosses into the unstable region.
Why Other Options Are Wrong:
- K > 20: excessive gain causes instability.
- 15 < K < 19: not consistent with stability range.
- K < 6: insufficient gain can also destabilize due to pole migration.
- None of the above: incorrect since the stable region is known.
Common Pitfalls:
- Confusing open-loop gain margin with closed-loop stability range.
- Assuming stability improves indefinitely as K increases.
Final Answer:
8 ≤ K ≤ 14.