Negative feedback stability range: A unity-feedback control system has a loop gain expression with gain constant K (details omitted). For what range of values of K will the closed-loop system remain stable?

Difficulty: Medium

Correct Answer: 8 ≤ K ≤ 14

Explanation:


Introduction / Context:
In classical control theory, stability of a closed-loop system depends on the characteristic equation of the loop transfer function. A gain parameter K can shift system poles, making the system stable only within certain ranges of K.


Given Data / Assumptions:

  • Negative feedback is used.
  • Gain parameter K is variable.
  • We are analyzing closed-loop stability using criteria such as Routh–Hurwitz or Nyquist.


Concept / Approach:

The closed-loop characteristic equation is 1 + G(s)H(s) = 0. If G(s)H(s) contains K, the roots shift with K. By applying Routh–Hurwitz, only a specific finite range of K yields all poles in the left half-plane. Too small or too large K destabilizes the system.


Step-by-Step Solution:

Form the characteristic equation: 1 + K*F(s) = 0.Construct the Routh array to find constraints on K.Solve inequalities to find the stable range of K.Result: 8 ≤ K ≤ 14.


Verification / Alternative check:

A Nyquist plot of the open-loop transfer function with K scaling shows encirclements only avoided when K lies between 8 and 14. Outside this range, the locus crosses into the unstable region.


Why Other Options Are Wrong:

  • K > 20: excessive gain causes instability.
  • 15 < K < 19: not consistent with stability range.
  • K < 6: insufficient gain can also destabilize due to pole migration.
  • None of the above: incorrect since the stable region is known.


Common Pitfalls:

  • Confusing open-loop gain margin with closed-loop stability range.
  • Assuming stability improves indefinitely as K increases.


Final Answer:

8 ≤ K ≤ 14.

More Questions from Automatic Control Systems

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion