Bringing the net price down with an extra discount: An article is listed at ₹1500. After a first discount of 20%, what additional single discount should be offered to bring the net price to ₹1104?

Introduction / Context:
Successive discounts multiply. Apply the first discount to get the intermediate price, then solve for the single second discount that lands the net amount at the target. This is a direct reverse-percentage application on the already discounted price, not on the original MRP.

Given Data / Assumptions:

• MRP M = ₹1500.
• First discount = 20% ⇒ price after first = 0.8M = ₹1200.
• Target net price = ₹1104.

Concept / Approach:
Let x be the additional discount rate on ₹1200. Then 1200 * (1 − x) = 1104. Solve for x and express as a percentage.

Step-by-Step Solution:

Verification / Alternative check:
Net factor from MRP: 0.8 * 0.92 = 0.736; 1500 * 0.736 = ₹1104, confirming.

Why Other Options Are Wrong:
10%, 12%, 15%, 6% do not reduce ₹1200 to ₹1104 exactly.

Common Pitfalls:
Applying the second discount to the original MRP instead of the already discounted base of ₹1200.

Final Answer:
8 %