Difficulty: Easy
Correct Answer: digital; analog
Explanation:
Introduction:
A core task at the physical layer is adapting the form of information to suit the channel. Computers generate discrete-time, discrete-amplitude data (bits), but many practical channels—especially legacy copper loops and radio links—are optimized for band-limited, continuous-time waveforms. This question tests whether you know the direction of conversion performed by a modulator before transmission.
Given Data / Assumptions:
Concept / Approach:
Modulation maps digital symbols onto the parameters of a carrier—amplitude, frequency, or phase—creating an analog passband waveform. Common schemes include ASK, FSK, PSK, and QAM. The receiver applies demodulation to recover the original symbols. This pair of operations (modulate/demodulate) explains the portmanteau “modem.” Therefore, the correct fill-in is: a modulator converts a digital signal to an analog signal suitable for the channel.
Step-by-Step Solution:
Identify the domain mismatch: digital source vs. analog-friendly channel.Recall the role of a modulator: map bits/symbols to carrier waveform parameters.State the transformation: digital → analog at the transmitter.Conclude that the correct pair is “digital; analog.”
Verification / Alternative check:
Consider a classic telephone-line modem: it accepts serial digital data and outputs audio-frequency tones. Similarly, cellular “modems” produce RF waveforms from digital packets.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing the direction of conversion (mixing up modulator vs. demodulator) or treating specific schemes (FSK, PSK) as if they described the input/output domains.
Final Answer:
digital; analog
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