For three variables A, B, C, write the canonical Sum-of-Minterms for Y = Σ m (1, 3, 5, 7). Which expression is correct?

Difficulty: Medium

Correct Answer: Y = A'B'C + A'BC + AB'C + ABC

Explanation:


Introduction / Context:
Canonical forms (Sum-of-Minterms and Product-of-Maxterms) are foundational in logic design, enabling systematic simplification and implementation using standard gates.



Given Data / Assumptions:

  • Minterms: m(1, 3, 5, 7).
  • Variables ordered as A (MSB), B, C (LSB).


Concept / Approach:

Each minterm index corresponds to the binary pattern of ABC. Index → bits: 1 → 001, 3 → 011, 5 → 101, 7 → 111. A 0 bit means complemented variable, a 1 bit means uncomplemented.



Step-by-Step Solution:

m1 (001) → A'B'Cm3 (011) → A'BCm5 (101) → AB'Cm7 (111) → ABCSum them: Y = A'B'C + A'BC + AB'C + ABC


Verification / Alternative check:

Create a 3-variable truth table for indices 1,3,5,7 and confirm outputs are 1 only at those rows. K-map grouping also matches this canonical SOP.



Why Other Options Are Wrong:

  • Options with any term having a wrong complemented/uncomplemented variable do not match the specified minterm index.
  • Expressions including C' for indices whose LSB is 1 are invalid for this set.


Common Pitfalls:

Misordering variables (e.g., using C as MSB) and mixing up complements when translating index to literals.



Final Answer:

Y = A'B'C + A'BC + AB'C + ABC

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