Ideal-gas specific heats – identities connecting cp, cv, γ, and R Which of the following relations correctly connect specific heats at constant pressure and volume with the gas constant and γ = cp/cv?
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Acp / cv = γ (definition only)
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Bcp − cv = R
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Ccp = γ * R / (γ − 1) and cv = R / (γ − 1)
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DBoth (b) and (c)
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Ecp − cv = γ * R
Answer
Correct Answer: Both (b) and (c)
Explanation
Introduction / Context:For ideal gases with temperature-independent specific heats over a range, cp, cv, γ, and the gas constant R are linked by simple identities used throughout thermodynamics and gas dynamics.
Given Data / Assumptions:
- Ideal-gas behaviour.
- Specific heats cp and cv are taken as constants over the temperature interval.
- γ is defined as cp/cv.
Concept / Approach:From the ideal-gas relations and definitions, two cornerstone identities follow: cp − cv = R and cp/cv = γ. Combining them yields convenient forms for cp and cv in terms of R and γ: cp = γR/(γ − 1) and cv = R/(γ − 1).
Step-by-Step Solution:Start with cp − cv = R.Use γ = cp/cv ⇒ cp = γcv.Substitute into cp − cv = R → γcv − cv = R → cv(γ − 1) = R.Solve: cv = R/(γ − 1) and cp = γR/(γ − 1).
Verification / Alternative check:Dimensional check: cp, cv, and R share units J/(kg·K) (for specific values); formulas are dimensionally consistent. Plugging back reproduces cp − cv = R and γ = cp/cv.
Why Other Options Are Wrong:
- (a) is true by definition but incomplete alone; the question asks for relations connecting to R as well.
- (e) cp − cv = γR is incorrect; it would imply cp/cv varies improperly with R.
Common Pitfalls:Confusing molar vs. specific (per mass) quantities; the same relations hold for both as long as R is the corresponding gas constant (Rmolar or Rspecific).
Final Answer:Both (b) and (c)