Ideal Gas Relation Between Specific Heats and Gas Constant For a calorically perfect gas, the gas constant R equals the difference between the specific heats at constant pressure and constant volume: R = Cp − Cv.

Difficulty: Easy

Correct Answer: difference

Explanation:


Introduction / Context:
Linking specific heats to the gas constant is foundational for ideal-gas property relations and for deriving many isentropic and energy equations used in thermodynamics and compressible flow.


Given Data / Assumptions:

  • Ideal-gas behavior with constant specific heats (calorically perfect).
  • Definitions: Cp is at constant pressure, Cv at constant volume.
  • R is the specific gas constant (per unit mass).


Concept / Approach:

The Mayer relation gives Cp − Cv = R. Physically, Cp exceeds Cv because at constant pressure the gas must do boundary work during heating, requiring extra heat input per unit temperature rise compared to constant-volume heating.


Step-by-Step Solution:

Start from h = u + pv for ideal gases (with h = CpT, u = CvT).Differentiate: dh/dT − du/dT = vdp/dT + pdv/dT.For ideal gas, pv = R*T and manipulations lead to Cp − Cv = R.Conclude R equals the difference of the two specific heats.


Verification / Alternative check:

For air near room temperature: Cp ≈ 1.005 kJ/kg-K, Cv ≈ 0.718 kJ/kg-K, difference ≈ 0.287 kJ/kg-K, matching R for air.


Why Other Options Are Wrong:

Sum, product, or ratio do not appear in the Mayer relation and have no general meaning for R. Geometric mean is irrelevant.


Common Pitfalls:

Using molar quantities without noting units; mixing universal gas constant Ru with specific R (R = Ru/M).


Final Answer:

difference

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