Thin cylindrical pressure vessel: For a cylinder of diameter d and thickness t under internal pressure p, what is the longitudinal (axial) membrane stress in the shell?

Difficulty: Easy

Correct Answer: p d / (4 t)

Explanation:


Introduction / Context:
Thin-walled pressure vessels develop two principal membrane stresses: circumferential (hoop) and longitudinal (axial). Correct formulas are vital for sizing thickness and checking allowable stress compliance in boilers, tanks, and pipelines.


Given Data / Assumptions:

  • Thin cylinder, t ≪ d.
  • Internal pressure p; ends closed.
  • Uniform membrane stresses; neglect radial stress.


Concept / Approach:
Equilibrium on a free-body of half the vessel gives hoop stress sigma_h = p d / (2 t). Equilibrium on the end cap gives longitudinal stress sigma_L = p d / (4 t). The longitudinal stress is half the hoop stress in a thin cylinder with closed ends.


Step-by-Step Solution:

Hoop: sigma_h = p d / (2 t).End equilibrium: p * (π d^2 / 4) balanced by 2 * sigma_L * t * (d / 2) * π → sigma_L = p d / (4 t).Hence the longitudinal stress is p d / (4 t).


Verification / Alternative check:
Check ratio: sigma_h / sigma_L = 2, consistent with thin cylinder theory.


Why Other Options Are Wrong:

  • p d / t and 2 p d / t are excessive (do not match equilibrium).
  • p d / (2 t) is the hoop, not longitudinal, stress.
  • p d / (6 t) has no basis in thin-cylinder derivation.


Common Pitfalls:
Using hoop formula for both directions; forgetting that end closures create axial stress; applying thick-cylinder relations to thin shells.


Final Answer:
p d / (4 t)

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