Simply supported beam with a central point load: Does the maximum bending moment occur at the point of loading (i.e., at midspan)?

Difficulty: Easy

Correct Answer: True

Explanation:


Introduction / Context:
For a simply supported beam under a single central point load, identifying where the maximum bending moment occurs is fundamental. Designers use this to select section size, reinforcement, and to estimate deflection and stresses safely.



Given Data / Assumptions:

  • Beam is simply supported at both ends.
  • A single point load P acts at the midspan (center).
  • Material is linearly elastic; self-weight ignored for clarity.


Concept / Approach:
The shear force diagram changes sign at the location of maximum bending moment. For a symmetric beam and centrally placed load, the symmetry dictates that the maximum moment occurs at the midspan under the load.



Step-by-Step Solution:

Support reactions: R_A = R_B = P/2Shear just left of midspan: V = +P/2; just right: V = −P/2Bending moment at a distance x from left: M(x) = R_A * x for x < L/2At midspan: M_max = R_A * (L/2) = (P/2) * (L/2) = P * L / 4This is the maximum because the shear changes sign there.


Verification / Alternative check:
From calculus, dM/dx = V. Setting V = 0 gives the extremum at midspan; checking neighbouring values confirms a maximum.



Why Other Options Are Wrong:
False or conditional statements contradict the shear sign-change rule and symmetry for a central point load on a simply supported beam.



Common Pitfalls:
Confusing with uniformly distributed loads (UDL) or off-center point loads; mixing simply supported with fixed-ended boundary conditions.



Final Answer:

True

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