Elastic constants relationship check: If the modulus of elasticity E equals twice the modulus of rigidity G (i.e., E = 2G), then Poisson's ratio ν is equal to zero. Is this statement correct?

Difficulty: Easy

Correct Answer: Correct

Explanation:


Introduction / Context:
Elastic constants of isotropic materials are interrelated. Recognizing the standard relationship among E (Young's modulus), G (shear modulus), and ν (Poisson's ratio) is essential in stress–strain analysis and finite element modeling.


Given Data / Assumptions:

  • Isotropic, homogeneous, linear elastic material.
  • Given that E = 2G.


Concept / Approach:
The standard relation for isotropic materials is
E = 2 * G * (1 + ν)
Rearranging gives ν = (E / (2G)) − 1. Substituting E = 2G directly yields ν = 0.


Step-by-Step Solution:

Start with E = 2 * G * (1 + ν)Given E = 2G → 2G = 2G * (1 + ν)Divide both sides by 2G (nonzero): 1 = 1 + ν → ν = 0


Verification / Alternative check:
Typical metals have ν around 0.25 to 0.35, which would give E closer to about 2.5G to 2.7G. The special case ν = 0 indeed makes E exactly 2G, matching the provided statement.


Why Other Options Are Wrong:

  • “Incorrect” conflicts with the exact algebraic relation.
  • “Depends on temperature only” and “Correct only for plastics” are irrelevant; ν is determined from the relation, not material class per se.
  • “Cannot be determined” is false because E = 2G fully determines ν = 0 for isotropy.


Common Pitfalls:
Applying the relation to anisotropic materials (where it does not hold) or confusing true values with approximate empirical ranges for specific materials.


Final Answer:
Correct

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