Difficulty: Medium
Correct Answer: OQ (the abscissa/projection of the plane point on the normal-stress axis)
Explanation:
Introduction / Context:
Mohr’s circle graphically relates normal and shear stresses acting on rotated planes. For any plane at a physical angle θ from a reference principal plane, the corresponding point on Mohr’s circle lies at an angle 2θ from the principal stress point.
Given Data / Assumptions:
Concept / Approach:
On Mohr’s circle, the horizontal axis is normal stress (σ), and the vertical axis is shear stress (τ). The normal stress on a plane equals the abscissa of the representative point, i.e., the horizontal projection from the origin to that point’s σ-coordinate.
Step-by-Step Solution:
Locate center C at σ_avg = (σ1 + σ2)/2.Construct the circle with radius R = (σ1 − σ2)/2.Rotate from the minor principal plane by angle 2θ to find point P.Drop a horizontal projection from P to the σ-axis → this distance from origin is OQ, the normal stress.
Verification / Alternative check:
Coordinates of P satisfy σ = σ_avg + R cos(2θ) and τ = R sin(2θ). The normal stress is the σ-coordinate only, which is exactly the horizontal projection OQ.
Why Other Options Are Wrong:
OC is the offset to the circle center, not the stress on a plane; OP mixes σ and τ components; PQ represents shear magnitude; CQ is partial and not referenced to the origin.
Common Pitfalls:
Confusing physical angle θ with 2θ on the circle; reading radial length instead of horizontal projection for σ; sign conventions for clockwise/counter-clockwise rotations.
Final Answer:
OQ (the abscissa/projection of the plane point on the normal-stress axis)
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