Axial strain calculation: A bar of length L metres extends by l millimetres under a tensile force P. What is the engineering strain produced in the bar?

Difficulty: Easy

Correct Answer: 0.001 l / L

Explanation:


Introduction / Context:
Strain is the non-dimensional measure of deformation and is defined as change in length divided by original length. Careful unit handling is essential when lengths are given in different units.



Given Data / Assumptions:

  • Original length = L metres.
  • Extension = l millimetres.
  • Small, uniform axial strain (linear elastic range).


Concept / Approach:
Engineering strain epsilon = delta_L / L_0. Convert all lengths to consistent units before forming the ratio to ensure a dimensionless quantity.



Step-by-Step Solution:

Convert extension to metres: delta_L = l mm = (l / 1000) m.Original length L_0 = L m.Compute strain: epsilon = (l / 1000) / L = 0.001 * (l / L).Hence epsilon = 0.001 l / L (dimensionless).


Verification / Alternative check:
Unit check: numerator and denominator both in metres; the ratio is unitless as required for strain.



Why Other Options Are Wrong:

  • l / L: ignores unit conversion; would be 1000× too large.
  • 0.1 l / L and 0.01 l / L: incorrect conversion factors.


Common Pitfalls:
Forgetting to convert millimetres to metres or mixing up engineering strain with percentage strain (%strain = 100 * epsilon).



Final Answer:
0.001 l / L

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