Maximum rotor (diagram) efficiency condition for an impulse stage:\nThe impulse turbine rotor efficiency reaches a maximum value of 0.5 * cos^2(α), where α is the nozzle exit angle, under which blade condition?

Difficulty: Medium

Correct Answer: blades are equiangular and frictionless

Explanation:


Introduction / Context:
Rotor (diagram) efficiency in impulse turbines depends on velocity triangles, blade speed ratio, and blade geometry. A key textbook result is the maximum efficiency achievable for given nozzle exit angle α when blades are designed to minimize losses and have symmetric (equiangular) inlet and outlet relative flow angles.


Given Data / Assumptions:

  • Impulse staging: pressure drop in nozzles, ideally constant pressure in moving blades.
  • Nozzle exit absolute velocity makes an angle α to the wheel tangent.
  • Blade friction neglected when velocity coefficient ≈ 1.
  • Equiangular blades: inlet and outlet relative flow angles equal in magnitude.


Concept / Approach:
Analyzing the velocity triangles and optimizing with respect to blade speed ratio yields a closed-form expression for the maximum rotor (diagram) efficiency. For equiangular and frictionless blades, the optimum gives η_r,max = 0.5 * cos^2 α for the stated condition. This relation highlights the importance of keeping α modest (to increase cos α) and ensuring high-quality, low-loss blade passages to approach the theoretical limit.


Step-by-Step Solution:

Construct inlet and outlet velocity triangles with nozzle angle α and equiangular blades.Express work per unit mass in terms of whirl components and blade speed.Differentiate with respect to blade speed ratio and set derivative to zero to find optimum.Substitute optimum into efficiency expression to obtain η_r,max = 0.5 * cos^2 α.


Verification / Alternative check:
Standard turbine textbooks present this derivation; numerical checks with typical α (for example 20–30 degrees) give plausible maximum efficiencies in the 0.35–0.44 range, consistent with single-stage impulse expectations when only rotor efficiency is considered (overall stage efficiency will be lower after accounting for nozzle and mechanical losses).


Why Other Options Are Wrong:

  • Equiangular only: Without assuming frictionless flow (velocity coefficient unity), losses reduce the maximum below the ideal expression.
  • Velocity coefficient unity only: Symmetry (equiangular) is also required to reach the stated form.
  • Blade solidity 0.65: Solidity influences losses and flow turning but does not by itself produce the stated closed-form maximum.


Common Pitfalls:
Confusing rotor (diagram) efficiency with overall stage efficiency; mixing the result η_r,max = cos^2 α (a different assumption set) with the present 0.5 * cos^2 α expression.


Final Answer:
blades are equiangular and frictionless

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