Difficulty: Medium
Correct Answer: The diameter of an equivalent pipe is equal to that of a compound pipe
Explanation:
Introduction / Context:
Multiple pipes in series with different diameters and lengths can be replaced by one “equivalent” pipe that yields the same discharge under the same head loss. This simplification is frequently used in network calculations and preliminary sizing. Understanding what stays the same and what changes in the equivalent representation is key to correct modeling.
Given Data / Assumptions:
Concept / Approach:
For a compound pipe in series, the total head loss h_f,total is the sum of losses over each segment. An equivalent single pipe is defined such that it carries the same Q with the same total h_f across the same overall length (often taken as the geometric length sum or an adjusted “equivalent length” including fittings). The required equivalent diameter is then computed from Darcy–Weisbach or Hazen–Williams; it generally differs from any individual segment diameter and from a simple average.
Step-by-Step Solution:
Verification / Alternative check:
Using Darcy–Weisbach with f assumed constant for a first pass: h_f ∝ (L/D^5) * Q^2 for laminar or with appropriate friction relations in turbulent range. Aggregating L/D^5 terms shows D_eq depends on a weighted combination, not equality to compound-pipe diameters.
Why Other Options Are Wrong:
Common Pitfalls:
Assuming D_eq equals arithmetic or geometric mean of component diameters; neglecting minor-loss contributions to equivalent length; mixing Darcy and Hazen–Williams forms without consistent parameters.
Final Answer:
The diameter of an equivalent pipe is equal to that of a compound pipe
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