Difficulty: Easy
Correct Answer: the change in momentum suffered by rubber ball is more than the lead ball
Explanation:
Introduction / Context:
This classic comparison illustrates impulse, coefficient of restitution, and how rebound affects momentum change. It links to collision analysis, sports physics, and materials selection for impact absorption.
Given Data / Assumptions:
Concept / Approach:
Change in momentum Δp = p_final − p_initial (vector). Take the approach direction as positive. Lead: initial momentum = +mu; final ≈ 0 ⇒ |Δp_lead| ≈ mu. Rubber: initial = +mu; final = −mv ⇒ Δp_rubber = −mv − (+mu) = −m(u + v) ⇒ magnitude |Δp_rubber| = m(u + v), which is greater than mu because v > 0.
Step-by-Step Solution:
Lead: |Δp| ≈ mu.Rubber: rebounds ⇒ |Δp| = m(u + v) > m*u.Therefore, the rubber ball experiences a larger magnitude of momentum change.Impulse equals change in momentum, so the wall delivers a larger impulse to the rubber ball.
Verification / Alternative check:
Coefficient of restitution e > 0 for rubber; e ≈ 0 for lead. Higher e implies a more negative final velocity relative to the incident direction, increasing |Δp|.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
the change in momentum suffered by rubber ball is more than the lead ball
Discussion & Comments