Gas welding safety and gas generation: The statement ‘‘Low-pressure acetylene for welding is produced at the job site by the chemical reaction between water and calcium carbonate’’ is — choose the correct assessment based on standard carbide generators and chemistry.
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AIncorrect
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BCorrect
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CConditionally correct only at high temperatures
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DCorrect for laboratory-grade acetylene production
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ECorrect when using dissolved acetylene cylinders
Answer
Correct Answer: Incorrect
Explanation
Introduction / Context:
Acetylene (C2H2) is a common fuel gas in oxy–acetylene welding. Historically, portable generators produced acetylene on site. Knowing the correct reactants is vital for both safety and exam accuracy.
Given Data / Assumptions:
- ‘‘Low-pressure acetylene’’ refers to generator-produced gas (legacy practice).
- Question cites water reacting with calcium carbonate.
- Standard generator chemistry should be applied.
Concept / Approach:
The canonical reaction in acetylene generators is between water and calcium carbide (CaC2): CaC2 + 2H2O → C2H2 + Ca(OH)2. Calcium carbonate (CaCO3) does not yield acetylene upon contact with water; it is limestone and would require acid to evolve CO2, not C2H2. Therefore, the statement is incorrect.
Step-by-Step Solution:
1) Recall correct reagent: calcium carbide, not calcium carbonate.2) Write the reaction with water: CaC2 + 2H2O → C2H2 + Ca(OH)2.3) Conclude the provided statement is false because CaCO3 cannot produce acetylene with water.Verification / Alternative check:
Industrial practice has largely shifted to dissolved acetylene in cylinders (acetone/DMF), but where on-site generation is used, the reagent remains CaC2, confirming the correction.
Why Other Options Are Wrong:
- Correct / Conditionally correct / Lab-grade / Cylinder-based: all contradict the fundamental chemistry; cylinders contain dissolved acetylene, not generated from CaCO3 on site.
Common Pitfalls:
- Confusing carbide with carbonate due to similar names.
- Assuming any calcium compound with water can produce acetylene—only CaC2 does.
Final Answer:
Incorrect