Impact mechanics — kinetic energy loss In a direct (head-on) impact between two bodies, the loss of kinetic energy _____ on the value of the coefficient of restitution (e).

Difficulty: Easy

Correct Answer: depends

Explanation:


Introduction / Context:
The coefficient of restitution e measures how “bouncy” a collision is. It directly influences post-impact relative speed and therefore the change in kinetic energy. Understanding this dependence is crucial in collision analysis in mechanics and vehicle safety.



Given Data / Assumptions:

  • Straight-line, head-on impact.
  • Coefficient of restitution e in the range 0 ≤ e ≤ 1.
  • No external impulses during the short impact interval.


Concept / Approach:
For two masses m1 and m2 with initial relative speed u_rel and final relative speed v_rel, restitution states: v_rel = e * u_rel (opposite direction). Total kinetic energy change depends on both masses and e. Perfectly elastic (e = 1) collisions conserve kinetic energy; perfectly inelastic (e = 0) collisions maximize kinetic energy loss for the given masses and initial speeds.



Step-by-Step Solution:

Use momentum conservation for the system to get final velocities in terms of e.Compute initial and final kinetic energies: K_i and K_f.Energy loss ΔK = K_i − K_f is a function of e (larger loss for smaller e).


Verification / Alternative check:
Special cases: e = 1 → ΔK = 0 (no loss). e = 0 → bodies stick together (maximum loss). Intermediate values yield intermediate losses, confirming dependence on e.



Why Other Options Are Wrong:

  • Does not depend / always zero: Contradicted by the limiting cases above.
  • Independent of masses or relative speed: ΔK also depends on masses and initial relative speed; e is one of several parameters.


Common Pitfalls:
Assuming momentum conservation implies energy conservation. Momentum is always conserved for isolated impacts; kinetic energy is not unless e = 1.



Final Answer:
depends


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