Impact mechanics — kinetic energy loss In a direct (head-on) impact between two bodies, the loss of kinetic energy _____ on the value of the coefficient of restitution (e).
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Adepends
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Bdoes not depend
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Cis always zero
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Dis independent of masses
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Eis independent of relative speed
Answer
Correct Answer: depends
Explanation
Introduction / Context:The coefficient of restitution e measures how “bouncy” a collision is. It directly influences post-impact relative speed and therefore the change in kinetic energy. Understanding this dependence is crucial in collision analysis in mechanics and vehicle safety.
Given Data / Assumptions:
- Straight-line, head-on impact.
- Coefficient of restitution e in the range 0 ≤ e ≤ 1.
- No external impulses during the short impact interval.
Concept / Approach:For two masses m1 and m2 with initial relative speed u_rel and final relative speed v_rel, restitution states: v_rel = e * u_rel (opposite direction). Total kinetic energy change depends on both masses and e. Perfectly elastic (e = 1) collisions conserve kinetic energy; perfectly inelastic (e = 0) collisions maximize kinetic energy loss for the given masses and initial speeds.
Step-by-Step Solution:
Use momentum conservation for the system to get final velocities in terms of e.Compute initial and final kinetic energies: K_i and K_f.Energy loss ΔK = K_i − K_f is a function of e (larger loss for smaller e).Verification / Alternative check:Special cases: e = 1 → ΔK = 0 (no loss). e = 0 → bodies stick together (maximum loss). Intermediate values yield intermediate losses, confirming dependence on e.
Why Other Options Are Wrong:
- Does not depend / always zero: Contradicted by the limiting cases above.
- Independent of masses or relative speed: ΔK also depends on masses and initial relative speed; e is one of several parameters.
Common Pitfalls:Assuming momentum conservation implies energy conservation. Momentum is always conserved for isolated impacts; kinetic energy is not unless e = 1.
Final Answer:depends