In the following question, two equations numbered 1 and 2 are given. You have to solve both the equations and determine the relation between a and b. 1. 5a2-18a+9=0 2. 3b2+5b-2=0

Q: In the following question, two equations numbered 1 and 2 are given. You have to solve both the equations and determine the relation between a and b. 1. 5a2-18a+9=0 2. 3b2+5b-2=0

From solving 1 and 2 we get, 1. 5a(a-3)-3(a-3) = 0 (5a-3)(a-3) = 0 a = 3 or 3/5 2. 3b(b+2)-1(b+2) = 0 b = -2 or b = 1/3 Here when a = 3, a > b for b = -2 and b = 1/3 when a = 3/5. a > b for b = -2 and b = 1/3. Hence, it is clear that a > b.

a >= b
a <= b
a < b
a > b

Correct Answer: a > b

Explanation:

From solving 1 and 2 we get,

5a(a-3)-3(a-3) = 0

(5a-3)(a-3) = 0

a = 3 or 3/5

3b(b+2)-1(b+2) = 0

b = -2 or b = 1/3

Here when a = 3, a > b for b = -2 and b = 1/3

when a = 3/5. a > b for b = -2 and b = 1/3.

Hence, it is clear that a > b.

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