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Syllogism – Resolve the apparent contradiction Premises: 1) All students in my class are bright. 2) Manish is not bright. What follows?

Difficulty: Easy

Some students are not bright.
Manish must work hard.
All who are not bright are not students.
Manish is not a student of my class.
None of the above.

Correct Answer: Manish is not a student of my class.

Explanation:

Introduction / Context:
This is a categorical syllogism that examines class membership based on a property (“bright”). If membership in a set guarantees a property, and an individual lacks that property, then the individual cannot belong to the set. We apply this directly to the class and Manish.

Given Data / Assumptions:

P1: All students in my class are bright.
P2: Manish is not bright.
We use standard logic with no hidden premises.

Concept / Approach:
“All A are B” and “x is not B” implies “x is not A.” Here, A = “students in my class,” B = “bright,” and x = Manish. This is a contrapositive reasoning pattern.

Step-by-Step Solution:

Translate: Class students -> bright.Given: Manish is not bright.Therefore: Manish cannot be a student in the class.

Verification / Alternative check:

Assume Manish is a student in the class: then he must be bright (contradiction). Thus, he is not a student in the class.

Why Other Options Are Wrong:

A: Does not follow; P1 says all class students are bright.B: Irrelevant; effort is not a logical consequence here.C: Overgeneralizes to “all non-bright are non-students,” which is not stated globally.E: Invalid because D follows.

Common Pitfalls:

Assuming properties about all students everywhere rather than restricting to “my class.”

Syllogism – Resolve the apparent contradiction Premises: 1) All students in my class are bright. 2) Manish is not bright. What follows?

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