Difficulty: Easy
Correct Answer: Only conclusion I follows
Explanation:
Given data
Concept/Approach
Map attributes: If a subset (Swords) lies entirely within Rusty, then any particular Sword (sharp or not) is a Rusty thing. From 'Some Swords are Sharp' it follows that some Rusty things (those sharp swords) are Sharp. But we cannot assert existence of non-sharp swords.
Step-by-step evaluation
1) From Premise 2, every Sword is Rusty.2) Premise 1 gives at least one element that is both Sword and Sharp.3) Therefore that element is also Rusty ∧ Sharp ⇒ (I) holds.4) (II) requires an element that is Rusty but not Sharp; premises do not guarantee such an element (all swords could be sharp for all we know).Verification/Alternative
Countermodel for (II): Let all Swords be Sharp; both premises hold, but there is no Rusty ∧ ¬Sharp element. Hence (II) is not necessary.
Common pitfalls
Final Answer
Only conclusion I follows.
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