Classification – Descending letter triplets: select the odd one out. In three triplets the pattern is “−1 then −3” across letters (A=1 … Z=26); one triplet breaks this. Which triplet is different? Options: MLI, FEB, UTQ, SRN.

Introduction / Context:
Another standard pattern uses fixed negative jumps. We check whether each triplet descends by −1 and then by −3; the deviant triplet is the answer.

Given Data / Assumptions:

• Alphabet positions A=1 … Z=26.
• Triplets: MLI, FEB, UTQ, SRN.
• Target rule: first→second = −1; second→third = −3.

Concept / Approach:
Compute both jumps and compare with the target pattern.

Step-by-Step Solution:
MLI: M(13)→L(12)=−1; L(12)→I(9)=−3 ✔FEB: F(6)→E(5)=−1; E(5)→B(2)=−3 ✔UTQ: U(21)→T(20)=−1; T(20)→Q(17)=−3 ✔SRN: S(19)→R(18)=−1; R(18)→N(14)=−4 ✖

Verification / Alternative check:
Re-check R→N: 18 to 14 is indeed −4, confirming the violation.

Why Other Options Are Wrong:
MLI, FEB, UTQ: Each satisfies −1 then −3, hence they belong together.

Common Pitfalls:
Counting letters inclusively (which would distort the step sizes) or mixing up N and O around 14–15.

Final Answer:
SRN