Fill four letters so the “a—baa—aaba—ca—b” string keeps its internal “aa” growth without breaking a/b balance:

Difficulty: Easy

Correct Answer: abac

Explanation:

Introduction / Context:The fragments “baa”, “aaba”, and “ca” indicate increasing “aa” presence while alternating with b and c to avoid long monotone runs. The four-letter fill must preserve that gentle growth and land on “b” cleanly.

Given Data / Assumptions:

  • Pattern: a — baa — aaba — ca — b
  • Four letters inserted.
  • No long identical clusters.

Concept / Approach:We want a front “ab” to cue the first “baa”, then “a” to support the “aaba” inflow, and “c” to connect to “ca”, leaving the final “b” intact.

Step-by-Step Solution:

Insert “abac”.Seams around “…baa…”, “…aaba…”, and “…ca…” align with balanced a/b/c deployment.

Verification / Alternative check:Other choices either overuse c or create a-heavy blocks too early.

Why Other Options Are Wrong:

  • bcca / ccaa: Introduce too much c or a at the wrong time.
  • acaa: A-heavy at the tail, spoiling “…ca…b”.
  • None of these: Not applicable.

Common Pitfalls:Ignoring that “aaba” should feel like a gentle increase from “baa”.

Final Answer:abac

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