Lag network (RC low-pass) — does the output voltage lag the input in phase?

Difficulty: Easy

Correct Answer: True

Explanation:


Introduction / Context:
Lag networks (often realized as RC low-pass filters with output taken across the capacitor) are used for phase lag and amplitude attenuation at higher frequencies. This question checks phase intuition for such networks.


Given Data / Assumptions:

  • A passive RC network configured so that output is across the capacitor (classic lag configuration).
  • Sinusoidal steady-state operation at frequency ω.


Concept / Approach:
For an RC low-pass, the capacitor current leads the capacitor voltage by 90 degrees, but the capacitor voltage lags the input because the resistor introduces a voltage division with frequency-dependent phase. Thus, Vout (across C) lags Vin for ω > 0.


Step-by-Step Solution:

Transfer function (magnitude-phase): H(jω) = Vout/Vin = 1 / (1 + j * ω * R * C).Phase of H(jω) = −arctan(ω * R * C).Since −arctan(ωRC) ≤ 0 for ω ≥ 0, output angle is negative → output lags input.At ω = 0, phase = 0 degrees (no lag). As ω increases, lag increases toward −90 degrees.


Verification / Alternative check:
Phasor diagram: input phasor equals the vector sum of resistor and capacitor voltage phasors; the capacitor voltage trails the current by 90 degrees, placing it behind the input phasor in angle.


Why Other Options Are Wrong:

  • “False” would imply the output does not lag; that contradicts both H(jω) angle and basic RC phasor relations when output is taken across C.


Common Pitfalls:
Confusing lag vs lead networks. If output is taken across the resistor (RC high-pass), the output leads the input at many frequencies (lead network). The placement of the output node determines phase behavior.


Final Answer:
True

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