Decrement operator in while condition and post-loop values: predict x and y. int x = l, y = 6; // note: the source uses letter l (ell), not digit 1 while (y--) { x++; } System.out.println("x = " + x + " y = " + y);
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Ax = 6 y = 0
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Bx = 7 y = 0
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Cx = 6 y = -1
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DCompilation fails.
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Ex = 7 y = -1
Answer
Correct Answer: Compilation fails.
Explanation
Introduction / Context:This question examines two issues at once: the semantics of post-decrement in a while condition and the correctness of variable initialization. However, the code as written will not compile due to an undeclared identifier.
Given Data / Assumptions:
xis initialized withl(lowercase L), not the digit1.ystarts at 6 and is decremented after each loop-condition evaluation due toy--.
Concept / Approach:Before discussing loop mechanics, compilation must succeed. Since l is not declared anywhere, the compiler signals “cannot find symbol” for l, and the program never runs.
Step-by-Step Solution:Compilation stage: variable l is unresolved ⇒ error.No bytecode is produced; there is no runtime behavior to analyze.
Verification / Alternative check:Fix the initialization to int x = 1;. Then the loop runs 7 times (for y values 6→0 inclusive), yielding x = 8 and y = -1. But that is for the corrected version, not the original.
Why Other Options Are Wrong:All printed outputs assume successful compilation and execution.
Common Pitfalls:Misreading the letter l as the digit 1, and overlooking that post-decrement returns the old value before decrementing.
Final Answer:Compilation fails.