Home » Java Programming » Exceptions

What will be the output of the program? public class X { public static void main(String [] args) { try { badMethod(); System.out.print("A"); } catch (Exception ex) { System.out.print("B"); } finally { System.out.print("C"); } System.out.print("D"); } public static void badMethod() { throw new Error(); /* Line 22 */ } }

Correct Answer: C is printed before exiting with an error message.

Explanation:

Error is thrown but not recognised line(22) because the only catch attempts to catch an Exception and Exception is not a superclass of Error. Therefore only the code in the finally statement can be run before exiting with a runtime error (Exception in thread "main" java.lang.Error).

← Previous Question Next Question→

More Questions from Exceptions

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion