Java do-while with pre-increment in condition — compute final values of i and j.\n\ni = 1; j = 10;\ndo {\n if (i > j) {\n break;\n }\n j--;\n} while (++i < 5);\nSystem.out.println("i = " + i + " and j = " + j);\n\nWhat is printed?

Introduction / Context:
This trace problem tests order of evaluation in do-while loops, the effect of a pre-increment (++i) in the loop condition, and control-flow with break. You must track i and j across iterations.

Given Data / Assumptions:

• Initial values: i = 1, j = 10.
• Loop body decrements j after an early break check.
• The while condition uses ++i, so i is incremented before the comparison with 5.

Concept / Approach:
A do-while executes the body at least once. After each body, j is decremented, then i is pre-incremented for the condition check. The break guard if(i > j) is evaluated at the top of each iteration before decrementing j. Carefully update the variables step by step.

Step-by-Step Solution:

Verification / Alternative check:
Note that the if(i > j) never triggers; j remains larger until exit. A quick table confirms the sequence.

Why Other Options Are Wrong:

• Options with i=6 assume post-increment; the code uses pre-increment in the condition.
• Other j values are inconsistent with the four decrements.

Common Pitfalls:
Forgetting that do-while checks condition after the body and that ++i changes i before comparison.

Final Answer:
i = 5 and j = 6