January 7, 1992 was a Tuesday. Find the day of the week on January 7, 1997 (5 years later on the same date).

Introduction / Context:For same-date shifts across years, weekday changes by +1 per common year and +2 per leap year (if 29 Feb lies between the two dates). We move from 07-01-1992 to 07-01-1997.

Given Data / Assumptions:

• Start: Tue (Jan 7, 1992).
• Years crossed: 1992, 1993, 1994, 1995, 1996.

Concept / Approach:Count weekday shifts year-by-year. If 29 Feb of a leap year lies between the dates, add +2, otherwise +1 for common years.

Step-by-Step Solution:1992 (leap; Feb 29 lies between the two Jan 7 dates): +2.1993: +1, 1994: +1, 1995: +1.1996 (leap; Feb 29 between): +2.Total shift = 2 + 1 + 1 + 1 + 2 = 7 ≡ 0 (mod 7) → still Tuesday.

Verification / Alternative check:Calendar lookup confirms Jan 7, 1997 was Tuesday.

Why Other Options Are Wrong:They reflect partial counting or ignoring leap-year double shift.

Common Pitfalls:Applying +2 for a leap year even when 29 Feb is not between dates (not the case here; it is between).

Final Answer:Tuesday