Batch reactor kinetics – first-order irreversible, isothermal, variable volume For an isothermal batch reactor with a first-order irreversible reaction, which relation between conversion (X_A) and time (t) is applicable (even if volume changes with conversion)?

Difficulty: Medium

Correct Answer: -ln(1 - X_A) = k t

Explanation:


Introduction / Context:
Relating conversion to time is fundamental for reactor design and performance prediction. A common doubt is whether changing volume during reaction alters the classic first-order exponential behavior in batch systems.


Given Data / Assumptions:

  • Isothermal batch reactor.
  • Elementary first-order irreversible reaction: r_A = −k C_A.
  • Volume may vary with conversion due to stoichiometry (ε_A ≠ 0).


Concept / Approach:
For a batch system, the total moles of A, N_A, satisfy dN_A/dt = r_A V = −k C_A V. Because C_A = N_A/V, the product C_A V equals N_A. Hence dN_A/dt = −k N_A regardless of how V changes with time. This decouples the kinetics from the volume change for first-order reactions in batch mode and leads to an exponential decay of N_A and the familiar logarithmic conversion relation.


Step-by-Step Solution:

Write mole balance: dN_A/dt = −k N_A.Separate variables: dN_A/N_A = −k dt.Integrate: ln(N_A/N_A0) = −k t → N_A = N_A0 e^(−k t).Define conversion: X_A = 1 − N_A/N_A0 = 1 − e^(−k t).Rearrange: −ln(1 − X_A) = k t.


Verification / Alternative check:
Check limiting behavior: as t → 0, X_A → 0; as t grows, X_A approaches 1 asymptotically, consistent with first-order kinetics.


Why Other Options Are Wrong:

  • X_A = k t: Linear in time is characteristic of zero-order, not first-order.
  • ε_A * ln(1 − X_A) = k t: ε_A affects concentration–conversion relationships in flow reactors, not the batch first-order N_A decay law.


Common Pitfalls:
Assuming variable volume changes the exponential decay of N_A for first order in batch; it does not, because C_A V = N_A cancels V(t).


Final Answer:
-ln(1 - X_A) = k t

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