Difficulty: Medium
Correct Answer: -ln(1 - X_A) = k t
Explanation:
Introduction / Context:Relating conversion to time is fundamental for reactor design and performance prediction. A common doubt is whether changing volume during reaction alters the classic first-order exponential behavior in batch systems.
Given Data / Assumptions:
Concept / Approach:For a batch system, the total moles of A, N_A, satisfy dN_A/dt = r_A V = −k C_A V. Because C_A = N_A/V, the product C_A V equals N_A. Hence dN_A/dt = −k N_A regardless of how V changes with time. This decouples the kinetics from the volume change for first-order reactions in batch mode and leads to an exponential decay of N_A and the familiar logarithmic conversion relation.
Step-by-Step Solution:
Write mole balance: dN_A/dt = −k N_A.Separate variables: dN_A/N_A = −k dt.Integrate: ln(N_A/N_A0) = −k t → N_A = N_A0 e^(−k t).Define conversion: X_A = 1 − N_A/N_A0 = 1 − e^(−k t).Rearrange: −ln(1 − X_A) = k t.Verification / Alternative check:Check limiting behavior: as t → 0, X_A → 0; as t grows, X_A approaches 1 asymptotically, consistent with first-order kinetics.
Why Other Options Are Wrong:
Common Pitfalls:Assuming variable volume changes the exponential decay of N_A for first order in batch; it does not, because C_A V = N_A cancels V(t).
Final Answer:-ln(1 - X_A) = k t
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