Stoichiometry of urea synthesis — What are the inputs required for one complete turn of the urea cycle (to produce one urea)?
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A1 aspartic acid, 1 ammonia, 1 carbon dioxide, and 3 ATP
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B1 urea, 1 ammonia, 3 ATP, and 1 fumaric acid
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C1 fumaric acid, 1 urea, and 3 AMP
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DNone of the above
Answer
Correct Answer: 1 aspartic acid, 1 ammonia, 1 carbon dioxide, and 3 ATP
Explanation
Introduction / Context:The urea cycle has a defined stoichiometry because it converts toxic nitrogen into urea. Understanding its inputs is crucial for biochemistry, nutrition, and clinical medicine (e.g., hyperammonemia management).
Given Data / Assumptions:
- One urea molecule is produced per cycle turn.
- Two nitrogens are required: one from free ammonia, one from aspartate.
- Energy is supplied by three ATP molecules (four high-energy phosphate bonds because one ATP → AMP + PPi).
Concept / Approach:Key reactions: CPS I uses NH3, CO2, and 2 ATP to form carbamoyl phosphate. Later, argininosuccinate synthetase uses aspartate and 1 ATP (to AMP) to add the second nitrogen. Overall, one NH3, one aspartate, and one CO2 are consumed, with 3 ATP hydrolyzed (equivalent to 4 phosphoanhydride bonds), yielding one urea and one fumarate.
Step-by-Step Solution:
Account for nitrogen: NH3 (first) and Asp (second).Account for carbon: CO2 provides the carbonyl carbon of urea.Energy: 2 ATP in CPS I + 1 ATP in argininosuccinate synthetase = 3 ATP.Products: urea + fumarate, with ornithine regenerated.Verification / Alternative check:Metabolic flux analyses and textbook conventions consistently list these inputs for one urea molecule produced.
Why Other Options Are Wrong:
- Option B mixes inputs and products incorrectly.
- Option C lists products rather than the correct reactants and confuses ATP with AMP accounting.
- “None” is incorrect because Option A is accurate.
Common Pitfalls:Confusing “3 ATP” with “3 high-energy bonds”; the cycle actually consumes 4 high-energy bonds due to one ATP → AMP.
Final Answer:1 aspartic acid, 1 ammonia, 1 carbon dioxide, and 3 ATP