Boyce–Codd Normal Form (BCNF) — Determinants as Candidate Keys If a table has been normalized so that every determinant is a candidate key, then the table is in which normal form?

Introduction:
BCNF refines 3NF by tightening the condition on determinants. A determinant is any attribute (or set of attributes) on which some other attribute is fully functionally dependent. This question tests recognition of the hallmark definition of BCNF.

Given Data / Assumptions:

• A candidate key uniquely identifies rows in a table.
• BCNF requires that every determinant be a candidate key.
• We assume functional dependencies are known.

Concept / Approach:
3NF allows some non-key determinants if the dependent attributes are prime or meet certain conditions. BCNF removes this leniency: if an attribute set determines another, that attribute set must be a candidate key. Therefore, a table where all determinants are candidate keys is, by definition, in BCNF.

Step-by-Step Solution:
1) Identify determinants in the table.2) Verify each determinant equals a candidate key.3) If true for all, the table satisfies BCNF.

Verification / Alternative check:
Check sample dependencies; if any non-key attribute functionally determines another attribute, BCNF is violated, pointing to 3NF at best.

Why Other Options Are Wrong:

• 1NF/2NF/3NF: Weaker conditions; only BCNF enforces the determinant-as-key rule.
• DK/NF: Stronger still; not implied by the stated condition.

Common Pitfalls:
Confusing 3NF with BCNF. Remember: BCNF tightens the determinant condition beyond 3NF.

Final Answer:
BCNF