C#.NET properties — Sample has a Length property with only a set accessor (write-only). Which statements compile and run?

Introduction / Context:
A write-only property exposes only a set accessor and no get accessor. This question checks whether you can distinguish valid usage of such a property (assignment) from invalid usage (reading the value).

Given Data / Assumptions:

• Sample.Length exists and has only set.
• No static property named Length is defined on the type.
• Standard C# property rules apply.

Concept / Approach:
You can assign to a write-only property on an instance, for example m.Length = 10;. Any attempt to read it (store into a variable, use on the right-hand side, or print it) will not compile because there is no get accessor. Static references like Sample.Length are also invalid unless the property is static (not stated).

Step-by-Step Solution:

Verification / Alternative check:
Define public int Length { set { ... } } and compile; only direct assignments are legal.

Why Other Options Are Wrong:

• A/B/D: All require a getter.
• C/D: Also misuse type-qualified access with an instance property.

Common Pitfalls:
Confusing a write-only instance property with a static property; or assuming you can read a value after setting it.

Final Answer:
Sample m = new Sample(); m.Length = 10;