Difficulty: Medium
Correct Answer: 0.33
Explanation:
Introduction / Context
Force transmissibility T in vibration isolation quantifies how much dynamic force passes through a mount from a vibrating machine to its foundation. Designers aim for T < 1 (isolation) by operating above resonance (r > √2) with appropriate damping.
Given Data / Assumptions
Concept / Approach
The standard formula for force transmissibility is T = √(1 + (2ζr)²) / √((1 − r²)² + (2ζr)²), where ζ is damping ratio. For light damping (say ζ ≈ 0.05–0.1), r = 2 places the system well into the isolation region, making T significantly below unity and near one third.
Step-by-Step Solution
1) Substitute r = 2 into the formula: numerator √(1 + (4ζ)²); denominator √((1 − 4)² + (4ζ)²) = √(9 + (4ζ)²).2) For ζ = 0.05: numerator ≈ √(1 + 0.04) ≈ 1.02; denominator ≈ √(9 + 0.04) ≈ 3.00; hence T ≈ 1.02 / 3.00 ≈ 0.34.3) For ζ = 0.1: numerator ≈ √(1 + 0.16) ≈ 1.08; denominator ≈ √(9 + 0.16) ≈ 3.03; hence T ≈ 0.36.4) Light-damping values cluster near one third, commonly rounded to 0.33.Verification / Alternative check
As ζ → 0, T → 1/|1 − r²| = 1/3 ≈ 0.333 for r = 2, matching the isolation-limit estimate.
Why Other Options Are Wrong
Common Pitfalls
Final Answer
0.33
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