Difficulty: Easy
Correct Answer: A voltage source in series with a resistance
Explanation:
Introduction / Context:Thevenin’s theorem is a powerful simplification tool. It allows you to replace any linear, bilateral two-terminal network with an equivalent source and resistance that behave identically from the perspective of the external load. Recognizing the correct canonical form is essential before you compute V_TH and R_TH.
Given Data / Assumptions:
Concept / Approach:The Thevenin equivalent is defined as a single ideal voltage source V_TH in series with a single resistance R_TH (or impedance Z_TH). V_TH equals the open-circuit voltage at the terminals. R_TH equals the equivalent resistance seen looking back into the network with independent sources deactivated (voltage sources shorted, current sources opened), or equivalently the ratio of V_TH to I_SC for purely resistive linear circuits.
Step-by-Step Solution:
Compute V_TH by finding the open-circuit terminal voltage.Compute R_TH by deactivating independent sources and finding the resistance seen at the terminals (or use R_TH = V_TH / I_SC).Construct the equivalent: an ideal V_TH source in series with R_TH.Attach any load RL and analyze easily via a simple series division.Verification / Alternative check:Confirm equivalence by checking that, for any RL, the original network and the Thevenin model produce identical terminal voltage and current.
Why Other Options Are Wrong:
Current source in series with resistance: that is Norton converted incorrectly; Norton uses a current source in parallel with resistance.Series–parallel ladder or many sources: not a canonical reduced form.Transformer-only model: unrelated to the general linear two-terminal reduction unless the original network is specifically a transformer circuit.Common Pitfalls:Mixing up Norton and Thevenin forms; forgetting to deactivate sources properly when finding R_TH; applying the theorem to nonlinear networks.
Final Answer:A voltage source in series with a resistance
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