Difficulty: Easy
Correct Answer: 4
Explanation:
Introduction / Context:Understanding how enumeration works in .NET collections is essential for writing thread-aware code. Each call to GetEnumerator() on a collection such as ArrayList returns a new enumerator object that maintains its own iteration state. When multiple threads enumerate the same collection concurrently, the number of enumerators equals the number of active enumerations.
Given Data / Assumptions:
Concept / Approach:ArrayList implements IEnumerable and returns an IEnumerator via GetEnumerator(). Every call produces a distinct enumerator instance with its own cursor and version check. Enumerators are not thread-safe; they are lightweight objects designed to be used by a single enumeration context.
Step-by-Step Solution:
Each thread starts enumeration → it calls GetEnumerator() (implicitly via foreach) → returns a fresh IEnumerator.Therefore, with four simultaneous enumerations, there are four distinct IEnumerator objects.These enumerators are independent; advancing one does not advance the others.Verification / Alternative check:Create a test that calls GetEnumerator() multiple times on the same ArrayList and compare ReferenceEquals among the returned enumerators; each call yields a different object reference.
Why Other Options Are Wrong:1 or 2 or 3 assumes enumerator sharing, which does not occur automatically. “Depends on a project setting” is incorrect; enumerator creation is defined by the framework, not by IDE settings.
Common Pitfalls:Mutating the collection while enumerating causes InvalidOperationException because enumerators track the collection version. Also, enumerators are not thread-safe objects; if multiple threads need to enumerate, they should each have their own enumerator or coordinate access.
Final Answer:4
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