Combinatorics of the code: With four RNA bases taken three at a time, how many distinct codons exist in the standard genetic code?

Difficulty: Easy

Correct Answer: 64

Explanation:

Introduction / Context:Codons are triplets of nucleotides formed from four bases (A, U, G, C). Counting possible combinations is a basic question linking combinatorics and molecular biology.

Given Data / Assumptions:

  • Four symbols (A, U, G, C).
  • Ordered triplets (position matters).
  • Repetition allowed.

Concept / Approach:The number of ordered triplets with repetition from a set of four is 4^3. This yields the total number of possible codons recognized by the translation machinery.

Step-by-Step Solution:

Compute combinations with order and repetition: 4^3.Calculate: 4^3 = 4 * 4 * 4 = 64.Interpretation: 61 sense codons for amino acids plus 3 stop codons in the standard code.

Verification / Alternative check:Genetic code tables list 64 entries, confirming the combinatorial calculation.

Why Other Options Are Wrong:

  • 3: confuses number of bases with number of codons.
  • 20: number of standard amino acids, not codons.
  • Infinite: the triplet code yields a finite set of combinations.

Common Pitfalls:Mixing up amino acid count with codon count; forgetting that multiple codons can encode the same amino acid (degeneracy).

Final Answer:64

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