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Two metallic plate of equal thickness and coefficient thermal conductivity K1 and K2 put together face to face. A common plate is constructed. What is equivalent K?

Correct Answer: 2k1k2/k1+k2

Explanation:

We know that,


 


The equivalent K =   L 1   +   L 2 L 1 K 1 + L 2 K 2


 


where L1 & L2 are plate1 & Plate2 thicknesses, K1 & K2 are coefficient thermal conductivity of plate1 & Plate2 respectively.


 


But here L1 = L2 = L (say)


 


Then K = L+L/(L/K1 + L/K2)  =   2 K 1 K 2 K 1 + K 2


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