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A parallel-plate capacitor,with air in between the plates, has capacitance C. Now the space between the two plates of the capacitor is filled with a dielectric of dielectric constant 7. Then the value of the capacitance will become

Correct Answer: 7C

Explanation:

As  the  capacitance  is  charged  by the  factor  equal  to  the  value  of dielectric constant, Hence, C’ = kC = 7C


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