A parallel-plate capacitor,with air in between the plates, has capacitance C. Now the space between the two plates of the capacitor is filled with a dielectric of dielectric constant 7. Then the value of the capacitance will become
Correct Answer: 7C
Explanation:
As the capacitance is charged by the factor equal to the value of dielectric constant, Hence, C’ = kC = 7C
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