A copper wire of radius r and length lhas a resistance of R. A second copper wire with radius 2r and length lis taken and the two wires are joined in a parallel combination. The resultant resistance of the parallel combination of the two wires will …

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1st copper wire: R = pl/A = pl/ πr2 2ndcopper wire: R’ = p’l’/A’ = pl/(4 πr2) = R/4 If joined in parallel, (1/Req) = (1/R) + (1/R’) = 1/R + 4/R1/Req= 5/R Req= R/5

A copper wire of radius r and length lhas a resistance of R. A second copper wire with radius 2r and length lis taken and the two wires are joined in a parallel combination. The resultant resistance of the parallel combination of the two wires will be

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