Home » General Knowledge » Physics

For a certain reaction,DGq = -45 kJ/mol and DHq= -90 kJ/mol at 0°C. What is the minimum temperature at which the reaction will become spontaneous, ifDHq and DSq are independent of temperature?

Correct Answer: 546 K

Explanation:

T = 273 °K


Using the formula,


DGq = DHq –TDS


-45 = -90 –273 DS


DS = 0.164


Now since DHq and DSq are independent,T2= DH/DS = 45/0.164 = 273°K


Required Temp = 273 + 273 = 546°K


← Previous Question Next Question→

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion