Radioactivity decay: An isotope has a half-life of 2 hours. What fraction remains after 6 hours? Assume simple first-order decay. Choose the correct remaining fraction.

Question

Radioactivity decay: An isotope has a half-life of 2 hours. What fraction remains after 6 hours?  Assume simple first-order decay. Choose the correct remaining fraction.

Accepted Answer

Given Half-life t1/2 = 2 h; elapsed time t = 6 h. Calculation Number of half-lives = t / t1/2 = 6/2 = 3.Remaining fraction = (1/2)3 = 1/8 = 0.125. Final Answer 1/8 of the initial quantity remains.

Radioactivity decay: An isotope has a half-life of 2 hours. What fraction remains after 6 hours? Assume simple first-order decay. Choose the correct remaining fraction.

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