Difficulty: Easy
Correct Answer: 15
Explanation:
Introduction / Context:
Transformations that add or subtract the same amount to both the numerator and denominator create linear equations in the original numerator and denominator. Solving these simultaneously reveals the original fraction’s parts without guesswork.
Given Data / Assumptions:
Concept / Approach:
Convert each condition to an equation in n and d, then solve the pair. Because both outcomes are integers (4 and 7), n and d will be small whole numbers that satisfy both equations. Substitution or elimination are straightforward here.
Step-by-Step Solution:
Verification / Alternative check:
Original fraction 15/3 = 5. Check: (15 + 1)/(3 + 1) = 16/4 = 4 and (15 − 1)/(3 − 1) = 14/2 = 7, both matching the statements.
Why Other Options Are Wrong:
2, 3, 7, and 9 do not satisfy both linear conditions simultaneously when paired with an integer denominator.
Common Pitfalls:
Adding 1 to only the numerator or denominator, or assuming the result must remain a proper fraction rather than allowing integer results.
Final Answer:
15
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