When a block of ice floats on water in a pond or glass, approximately what fraction of its total volume remains above the water surface?

Difficulty: Easy

Correct Answer: 0.1 (about one tenth of the volume)

Explanation:


Introduction / Context:

This question is an application of Archimedes principle to the case of ice floating on water. Students often observe that ice cubes or icebergs have only a small portion visible above the water, while most of the volume remains submerged. Understanding the fraction of volume above water reinforces the relationship between density, buoyant force, and floating equilibrium.


Given Data / Assumptions:

  • A piece or block of ice floats at rest on the surface of liquid water.
  • We assume pure ice and pure water at conditions where both phases can coexist.
  • The density of ice is slightly less than that of water, often approximated as about 0.9 times water density.
  • We are interested in what fraction of the ice volume remains above the water surface.


Concept / Approach:

For a floating body in equilibrium, the weight of the body equals the buoyant force, which equals the weight of displaced fluid. Let rho_ice be the density of ice and rho_water be the density of water. The fraction of ice volume submerged is approximately rho_ice / rho_water. With rho_ice roughly 0.9 times rho_water, about 0.9 of the volume is submerged and 0.1 of the volume remains above water. Thus, around one tenth of the ice block sticks out above the surface, which matches common observations of floating ice and icebergs.


Step-by-Step Solution:

Step 1: Use Archimedes principle: weight of floating ice = weight of displaced water. Step 2: Let V be the total volume of the ice block and V_sub the submerged volume. Then rho_ice * V * g = rho_water * V_sub * g. Step 3: Simplify to V_sub / V = rho_ice / rho_water. Step 4: Use typical densities: rho_ice is about 0.9 times rho_water, so V_sub / V is approximately 0.9. Step 5: Therefore, the fraction above water is 1 minus 0.9, which is about 0.1, or one tenth of the total volume.


Verification / Alternative check:

Practical observation supports this theoretical estimate. An ice cube in a glass of water appears mostly submerged, with only a small cap visible. Photographs of icebergs at sea also show relatively small tops compared to their total size, with most of their mass underwater. These real world observations consistently suggest that roughly one tenth of the volume is above the surface. While the exact fraction depends slightly on temperature and purity, 0.1 is a good approximation for school level questions.


Why Other Options Are Wrong:

  • 0.5 (half of the volume): If half the ice were above water, then the density ratio would be drastically different and ice would be much lighter than water, which is not true.
  • 0.3 (about one third): This overestimates the above water portion; the actual fraction is closer to one tenth.
  • 1 (the whole block remains outside): This would mean ice does not sink at all and would not be floating in the usual sense, which contradicts observation.


Common Pitfalls:

Students may guess that half the block is above water because they think of symmetry, not density. Others may confuse the idea of floating with fully staying outside the liquid. Remember that floating means the weight of the displaced fluid balances the weight of the object. For materials like ice with density slightly less than water, most of the volume must be submerged to displace enough water, leaving only a small fraction above. Using the density ratio is a reliable method to avoid guessing.


Final Answer:

When ice floats on water, roughly 0.1 or about one tenth of its volume remains above the water surface.

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