8051 loop behavior with JNZ Will the following code lock the CPU in a loop? LOOP: MOV A, #00H JNZ LOOP

Difficulty: Easy

Correct Answer: False

Explanation:


Introduction / Context:
Understanding conditional jumps is essential in 8051 assembly. JNZ branches only when the accumulator is nonzero. This snippet deliberately loads zero before testing, so you must reason about what JNZ will do.


Given Data / Assumptions:

  • MOV A, #00H sets accumulator A = 0.
  • JNZ LOOP branches if A != 0.
  • No intervening instructions alter A.


Concept / Approach:
Immediately after loading 0, the condition for JNZ is false. Therefore, the jump is not taken and control falls through to the next instruction after JNZ, not back to LOOP.


Step-by-Step Solution:

1) Execute MOV A, #00H → A = 0.2) Execute JNZ LOOP → since A == 0, do not jump.3) Program continues linearly; there is no infinite loop.4) A loop would require A to be nonzero at the JNZ.


Verification / Alternative check:
Run on an 8051 simulator and watch the program counter: it does not branch to LOOP.


Why Other Options Are Wrong:

  • True: Incorrect because A equals zero at the test.
  • Only if A was nonzero before MOV: Prior value is overwritten by MOV.
  • Only when the stack is empty: Stack state is irrelevant to JNZ here.


Common Pitfalls:
Assuming JNZ checks a generic zero flag; it specifically checks the accumulator value.


Final Answer:
False — the code executes once and then falls through.

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