Difficulty: Medium
Correct Answer: It remains the same
Explanation:
Introduction / Context:
This is a classic conceptual question involving weight, forces and internal redistribution of mass in a system. A man is standing on the pan of a balance, holding a fish in one hand and a bucket of water in the other. The entire man–fish–bucket system is on the pan. The question asks what happens to the reading of the balance if the fish is transferred from his hand into the bucket of water. Understanding this scenario helps clarify that weight depends on the total mass, not how that mass is arranged internally within the system on the scale.
Given Data / Assumptions:
- The man, fish and bucket of water are all on the pan of the balance.
- Initially, the fish is in the man's hand; after the transfer, the fish ends up in the bucket of water.
- No water is spilled, and nothing leaves or enters the system during the transfer.
- The balance measures the total downward force (total weight) of everything resting on it.
Concept / Approach:
The balance reading depends on the total gravitational force exerted by all the objects on the pan. As long as the total mass on the pan remains constant, the total weight remains the same. Moving the fish from the man's hand into the bucket only redistributes the internal forces within the system. The apparent weight contributions of individual parts may shift, but the overall weight the balance supports does not change, provided no mass is lost (for example by spilling water) and no external support is introduced.
Step-by-Step Solution:
Step 1: Consider the initial state. The balance supports the combined weight of the man, the fish and the bucket of water.
Step 2: When the fish is in the man's hand, its weight is transmitted through the man's body to the balance.
Step 3: After the fish is transferred into the bucket, its weight is transmitted through the water and bucket to the balance.
Step 4: In both cases, the same fish is still part of the system, and its mass has not changed.
Step 5: The total mass on the pan (man + fish + bucket + water) is unchanged because nothing has been removed or added.
Step 6: Therefore, the total weight measured by the balance remains the same.
Verification / Alternative check:
You can think of the pan as supporting a single object whose mass is equal to the sum of all parts. Whether the fish is held in the man's hand or floats in the bucket, gravity pulls on it with the same force. The support provided by the pan must balance the same total weight before and after. This kind of reasoning is widely used in similar questions involving a person in a lift holding objects, or animals in cages placed on scales. In all such idealised cases, internal rearrangements do not affect the external weight reading if the total mass remains the same.
Why Other Options Are Wrong:
It increases: There is no extra mass added; moving the fish cannot increase total weight in an ideal situation without splashing or external forces.
It decreases: Again, no mass is removed from the pan, so the total weight cannot decrease simply because of internal rearrangement.
It first increases and then decreases: This suggests complicated transient effects, but in the idealised exam scenario such transient effects are ignored and the final equilibrium reading is the same as the initial one.
Common Pitfalls:
A common mistake is to think that when the fish goes into the water, some "buoyant force" reduces the weight, forgetting that the bucket and water together still transmit the full combined weight to the balance. Another confusion is to mix up apparent weight felt by parts of the system with the total weight measured by the scale. Always focus on whether the total mass on the scale has changed; if it has not, the reading must remain the same in equilibrium.
Final Answer:
The total weight on the balance remains the same when the fish is transferred into the bucket of water.
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