Difficulty: Easy
Correct Answer: Gets attenuated (magnitude decreases)
Explanation:
Introduction / Context:
The frequency response of linear time-invariant (LTI) systems is foundational for control and signal processing. A first-order process behaves like a low-pass filter. Understanding what such a system does to a sinusoidal input—without solving differential equations every time—helps predict attenuation and phase lag across frequencies.
Given Data / Assumptions:
Concept / Approach:
For LTI systems, a sinusoidal input at frequency ω produces a sinusoidal output at the same frequency, scaled in magnitude by |G(jω)| and shifted in phase by ∠G(jω). For a first-order low-pass, |G(jω)| = K / sqrt(1 + (ωτ)^2), which is ≤ K, showing attenuation that increases with ω. The frequency does not change; only amplitude is reduced and phase lags.
Step-by-Step Solution:
Verification / Alternative check:
Bode plots of a first-order system show a 0 dB plateau at low ω and a −20 dB/decade roll-off past the corner at 1/τ, confirming attenuation at higher frequencies.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing transient behaviour with steady-state sinusoidal response; only amplitude and phase change at the same frequency in steady state.
Final Answer:
Gets attenuated (magnitude decreases)
Discussion & Comments