Difficulty: Easy
Correct Answer: K * e^{-θ s} / (τ s + 1)
Explanation:
Introduction / Context:
The first-order plus dead time (FOPDT) model is the most widely used low-order approximation in process control, capturing dominant lag and transport delay for many thermal, flow, and composition loops. Recognizing its canonical transfer function form is essential for tuning (e.g., Ziegler–Nichols, Cohen–Coon) and for controller design heuristics.
Given Data / Assumptions:
Concept / Approach:
A dead time element multiplies any transfer function by e^{−θ s} (unity magnitude, frequency-dependent phase). A first-order lag is 1/(τ s + 1). Therefore, the FOPDT model is K * e^{−θ s} / (τ s + 1). Higher-order denominators or extra 1/s factors indicate different dynamics (second order or integrating behavior) and are not correct for a simple FOPDT.
Step-by-Step Solution:
Verification / Alternative check:
Frequency response of e^{−θ s} has |G| = 1 and phase = −ω θ, while 1/(τ s + 1) gives −tan^{-1}(ω τ) phase and 1/√(1 + (ω τ)^2) magnitude roll-off, matching FOPDT characteristics.
Why Other Options Are Wrong:
Common Pitfalls:
Modeling delay as extra lag terms; true transport delay is exponential in s.
Final Answer:
K * e^{-θ s} / (τ s + 1)
Discussion & Comments