Difficulty: Medium
Correct Answer: Conversion is the same in both cases, but the concentrations are different
Explanation:
Introduction / Context:
This question tests understanding of first-order kinetics in batch reactors when volume is either constant (typical liquid-phase assumption) or allowed to change (e.g., certain gas-phase systems). It probes whether conversion X and concentration C are affected the same way by volume changes for a first-order irreversible reaction.
Given Data / Assumptions:
Concept / Approach:
Conversion X is defined on moles of A, X = (NA0 − NA)/NA0. For first-order batch at a fixed k and fixed t, the exponential decay of NA (moles of A) is governed primarily by the integrated rate law. Differences arise in CA = NA/V. Thus, even when NA (and therefore X) matches at a given t, the concentrations will differ if the volumes differ.
Step-by-Step Solution:
For constant V: dCA/dt = −k CA ⇒ CA = CA0 exp(−k t); NA = V CA.For variable V(t): NA still decays based on kinetics, while CA = NA/V(t) differs because V changes.At the same t with the same k, the fraction of A reacted (conversion) can be the same; however, CA values are different as V differs.
Verification / Alternative check:
If volume expands, the same NA corresponds to a smaller CA; if volume contracts, CA is larger. Conversion depends on NA, not directly on V.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
Conversion is the same in both cases, but the concentrations are different
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