Correct Answer: 1/14
Explanation:
The 8 letters can be written in 8! ways.
 n(S) = 8!
 Let E be the event that the letters b,c,d,e always come together when the first 8 alphabets are written down.
 Now the letters a, (bcde), f, g and h can be arranged in 5! ways.
 The letters b,c,d and e can be arranged themselves in 4! ways.
 n(E) = 5! x 4!
 Now, the required P(E) = n(E)/n(S) = 5! x 4!/8! = 1/14
 Hence the answer is 1/14. 
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