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Problems on H.C.F and L.C.M
Find the least number which when divided by 12, 15, 20 and 24 leaves the same remainder 2 in each case?
122
120
124
126
Correct Answer:
122
Explanation:
Required number = LCM of (12, 15, 20, 24) + 2
= 120 + 2 = 122
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