Difficulty: Easy
Correct Answer: relative volatility is reasonably constant
Explanation:
Introduction:Fenske’s equation provides the minimum number of equilibrium stages required for a specified key-component split at total reflux. It is a powerful shortcut for preliminary column design when its assumptions are met. Recognizing those assumptions ensures correct application to binary and pseudo-binary separations.
Given Data / Assumptions:
Concept / Approach:
Under total reflux, the composition profile is governed by equilibrium alone. If the relative volatility α is reasonably constant from tray to tray, the separation factor per stage is constant, allowing the logarithmic form of the Fenske equation to predict stage count directly. Significant variation in α due to non-ideality or large temperature/composition swings undermines the equation’s accuracy and calls for rigorous methods (e.g., stage-by-stage simulation).
Step-by-Step Solution:
Define keys: light key (LK), heavy key (HK) with overall relative volatility α_LK,HK.Use Fenske: N_min = log[(x_D,HK/x_B,HK) * (x_B,LK/x_D,LK)] / log(α).Assume α ≈ constant → equation holds.Conclude that constancy of α is the central condition.Verification / Alternative check:
Process simulators show good agreement between Fenske and rigorous calculations for near-ideal binaries with mild α variation; discrepancies grow as α varies strongly.
Why Other Options Are Wrong:
B/C point to deviations that often make α composition-dependent; D: Fenske can be extended to multicomponent using effective keys but the core assumption remains constant α; E: Feed condition is irrelevant at total reflux.
Common Pitfalls:
Applying Fenske away from total reflux or to strongly non-ideal systems without checking α variability.
Final Answer:
relative volatility is reasonably constant
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